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Gaming Gurus: Strategy Expert Article Archive - Page 408
Additional Information on the Field Bet10 April 2011
Hi Stickman,
One thing I would add to your article on the Field Bet is that the bet is resolved on every roll.
Compare a $5 Place 5 bet (HA=4.00%) to a $5 3x12 Field (HA=2.78%) bet over a perfectly distributed 36 rolls.
Place 5 wins $7 four times and loses $5 six times for a net loss of $2.
Field wins $15 once, $10 once, and $5 fourteen times; and loses $5 twenty times for a net loss of $5.
Van
Hi Van,
You bring up a good point...read moreJest for Fun9 April 2011 Sign seen written on men's room wall in a Las Vegas casino:
"It's only a gambling problem if you're losing."
* * * * *
Math teacher to gambler's son, "Billy, tell the class how much is
two and two."
Billy: "Snake eyes."
* * * * *
The Flamingo Casino in Las Vegas was built by the notorious
mobster Bugsy Siegel...read moreDeal or No Deal8 April 2011 I have always loved playing games. I grew up long before the video generation and most of the games I played as a child were board games or card games. It didn't really matter. I just loved competing against my family, friends or anyone else I could entice into playing.
I guess my love of games is why I also enjoy watching certain games shows on television...read morePlease, no! It's not right!7 April 2011 In baseball there are many "unwritten codes" that are supposed to be followed by the ballplayers. For example, if your team is destroying the other team, your base runners are not to steal bases. Don't rub the area of your body where you were hit by a pitch; doing so shows you are not manly...read moreRNGs and bingo cards on Class II slots6 April 2011 The following letter is about Class II slot machines. Class II slots, unlike the Class III slots found in Las Vegas, Atlantic City, Tunica and elsewhere, do not determine the outcomes of their spins independently. They do not have random number generators (RNGs)...read moreTriple-zero roulette5 April 2011 Anna was a casual acquaintance in college, a friend of a friend of a friend who I used to run into at the odd party. I was more than a little surprised to receive a message from her via Facebook — and then I saw it was about gambling.
"At a charity casino night, they had a roulette wheel with three zeroes," she wrote...read moreHow do Edge and Chance of Winning a Bet Differ?4 April 2011 In casino gambling, edge indicates the fraction of every wager the joint should get to keep. Probability of winning suggests how frequently bets should pay off. Higher or lower edge means that the bosses keep more or less, not that a bet is less or more apt to win...read moreBig dice, little dice4 April 2011
Hey Frank:
I love your work.
I'm in the process of finishing your book Casino Craps: Shoot to Win! I have a question.
I've been practicing since August with the dice rig I built using some dice I bought at a liquor store. My girlfriend recently bought me some legit casino dice, which are much larger than the store-bought dice...read moreTaking Advantage of an Advantage: Part 3 – Kelly Betting3 April 2011 In last month’s article we discovered that
when employing proportional betting, choosing the fraction f of our stake that
we should risk when playing a positive game is tricky. In particular we noted
that if f is a large number (between 0 and 1), virtual ruin is almost
certain. Even lowering f to 0.3 was not sufficient to ensure that we would not
experience ruin. Is there any way to choose f that makes sense?
The development that follows is not as
rigorous as that presented by Kelly [3] and other practitioners. It is less
technical and more simplistic but does, I believe, convey the idea accurately.
We noted that by trying to optimize our
expected return over all possible paths (see last month’s article for the
definition of path), we included many paths that would terminate with our being
unable to continue betting. In these instances the longer we play, the worse
things get. The approach we now take is suggested by some of the discussion at
the end of last month’s article. If the game is positive, we want to be able to
play it for a long time. In such a scenario the law of large numbers (commonly
referred to in naive terms as the law of averages) says that for a large number
of trials, the ratio of wins to the number of trials will be close to the win
probability with a high likelihood. In symbols, w/n will be close to p.
Similarly, l/n will be close to q.
Another way of saying this is to say that np
will be close to w and nq will be close to l. How close? You’ll have to get
out your old probability book for that one I am going to skip that issue
though it is a real one (see [1], [4], and [6]). Recall that last month we
derived the expression
Sn
= (1 + f)w(1 – f)lS0 (1)
For large n we then have
Sn
~ (1 + f)np(1 – f)nqS0 (2)
where ~ stand for approximately equal. We can easily
rewrite (2) as
Sn
~ [(1 + f)p(1 – f)q]nS0 (3)
Defining the function G by
G(x) = (1
+ x)p(1 – x)q, 0 ≤ x ≤ 1 (4)
we can rewrite (3) as
Sn
~ [G(f)]nS0 (5)
The approximation indicated in expression (5)
makes it clear that the righthand side of this approximation determines how Sn
propagates. In particular, if G(f) is a number smaller than 1, then the right
hand side of (5) will get smaller and smaller as n increases. Similarly, if
G(f) is larger than 1, then the righthand side of (5) will increase as n
increases. Because this expression approximates Sn we can draw a
similar conclusion regarding Sn and the choice of f.
Notice that from expression (4) we see that
G(0) = 1 and G(1) = 0. What about values of f between 0 and 1. Here is where
a bit of calculus is handy. The derivative of G, written G’(x), is given by
the expression
G’(x) = [(p – q –
x)/(1 – x2)]G(x) (6)
For those of you who have had calculus, I leave the
derivation of (6) to you as an exercise; the rest of you will just have to take
my word for it. It is the interpretation of this formula that is important
here.
If one were to draw a graph of G on the interval from 0 to 1, the formula
given in (6) would give you the slope of the tangent line to the resulting
curve. Notice that G’(0) = p – q, which we have been assuming is positive.
That means that the function G(x) is increasing as x increases from 0. We know
that G(1) = 0, so G must reach a maximum at some point to the right of 0.
At such a point the tangent line to the curve would be a horizontal line and
thus have a slope of 0. Also G(x) would be positive at such a point; in fact
it would be greater than 1. Hence, since x is less than 1, 1 – x2
would also be positive. The only way to make the slope 0 at such a point would
be to take p – q – x = 0 or, in other words, to set x = p – q = e.
Here then is the Kelly Criterion. Simply set
f = e. In words, the fraction of our stake that we should risk is equal to the
advantage that we have. In our running example this would be 2%. Now we see
why we had such difficulty last month. The values of f that we chose were just
too large. If we set f = e, then G(e) is greater than 1 and is the maximum
value that we can take for G.
A few words are in order here...read moreWho Needs Training?2 April 2011 There is no such thing as a bad player only an untrained one.
That is my company motto. I thought up that motto based on long term observations while in the casino. In addition, if you go on the Internet or to the library as much as I do, you get to read a lot of data about gaming...read more |
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