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Gaming Guru
Why Being Too Clever by a Half Doubles the Casino's Edge3 April 2001
Solid citizens don't always discover this loophole in the laws of mathematics on their own. They sometimes see it in a book so they know it's gotta be true. And, some casinos reportedly don't allow simultaneous Do and Don't bets, which fact -- or rumor, anyway -- strengthens the sense of a secret system for select insiders. In reality this ill-conceived gimmick, far from eliminating the house advantage on craps line bets, exacerbates it. Betting both sides is the worst of both worlds. To picture the situation intuitively, you can consider only the flat portion of the wager because the odds don't affect the amount of the casino's theoretical "take." Normally, Pass bets have an advantage before the point is established, since they are paid even-money but have eight ways to win and only four to lose. Conversely, Don't Pass bets have an advantage after the point is established, since they pay even money but have six ways to win on any number with only three to lose on the four or 10, four on the five or nine, and five on the six or eight. Equal amounts on Pass and Don't Pass offer no way to win before or after the point is established, and one way to lose whatever's on the Pass line during the come-out. The folly of betting both sides can also be expressed in numbers -- percentages as well as dollars and cents. The house edge is 1.41 percent of the flat bet on Pass and 1.36 percent on Don't Pass. That's roughly $0.07 for $5 bet on either side. With $5 on both sides, the take is $0.07 twice, for a total of $0.14. To see exactly how edge works, imagine 1980 statistically-correct come-out episodes. Instances of wins and losses for Pass and Don't Pass bets are as shown in the accompanying table.
For bets on Pass, expectation is to lose a net of 1004 - 976 or 28 units during the 1980 episodes. At $5 each, this amounts to $140. And 28 divided by 1980 is 1.41 percent, by no coincidence the house edge on Pass bets. Likewise for Don't Pass, expectation is to lose a net of 976 - 949 or 27 units during the 1980 episodes. At $5 each, this would be $135. And 27 divided by 1980 is 1.36 percent, also by no coincidence, the edge on Don't Pass. A player who bets $5 each on Pass and Don't Pass will lose $5 in those rare cases when 12 rolls on the come-out. How rare? On the average, once every 36 times. Divide 1980 by 36 to get 55 as the number of 12s in 1980 statistically-correct come-outs. And $5 times 55 is $275, which happens to be the sum of the expected $140 and $135 losses on the separate $5 Pass and Don't Pass bets. What about the odds? This portion of the bet has no impact on the amount of expected loss. Rather, it increases the money players can put in action for the fee the casino hides in the form of the edge. The whole idea in a negative expectation game is to get the most action for the least fee, depending on volatility for a profitable session. Betting Pass and Don't Pass together, then taking or laying the odds on either, defeats this objective. Here's how the poet of the pits, Sumner A Ingmark, put it. Bettors who act too clever by a half, Recent Articles
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